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JEE Mains · Physics · STD 12 - 14. Semicondutor electronics

If a semiconductor photodiode can detect a photon with a maximum wavelength of \(400\, nm ,\) then its band gap energy is Planck's constant \(h=6.63 \times 10^{-34}\, J . s\) Speed of ligh \(c =3 \times 10^{8}\, m / s\)

  1. A \(2.0\; eV\)
  2. B \(1.5\; eV\)
  3. C \(3.1\; eV\)
  4. D \(1.1 \;eV\)
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Correct Answer

(C) \(3.1\; eV\)

Step-by-step Solution

Detailed explanation

\(\Delta E =\frac{h c }{\lambda e }=3.1\; eV\)
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