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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2020
  • Easy
  • MCQ

If a semiconductor photodiode can detect a photon with a maximum wavelength of \(400\, nm ,\) then its band gap energy is Planck's constant \(h=6.63 \times 10^{-34}\, J . s\) Speed of ligh \(c =3 \times 10^{8}\, m / s\)

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Answer & Solution

Correct Answer

(C) \(3.1\; eV\)

Step-by-step Solution

Detailed explanation

\(\Delta E =\frac{h c }{\lambda e }=3.1\; eV\)