JEE Mains · Physics · STD 12 - 1. Electric charges and fields
Four closed surfaces and corresponding charge distributions are shown below Let the respective electric fluxes through the surfaces be \({\phi _1},{\phi _2},{\phi _3}\) and \({\phi _4}\) . Then
- A \({\phi _1} < {\phi _2} = {\phi _3} > {\phi _4}\)
- B \({\phi _1} > {\phi _2} > {\phi _3} > {\phi _4}\)
- C \({\phi _1} = {\phi _2} = {\phi _3} = {\phi _4}\)
- D \({\phi _1} > {\phi _3} ; {\phi _2} < {\phi _4}\)
Answer & Solution
Correct Answer
(C) \({\phi _1} = {\phi _2} = {\phi _3} = {\phi _4}\)
Step-by-step Solution
Detailed explanation
The net fluw linked with closed surfaces \(S_{1}\), \(\mathrm{S}_{2}, \mathrm{S}_{3} \& \mathrm{S}_{4}\) are For surface \(S_{1}, \phi_{1}=\frac{1}{\varepsilon_{0}}(2 q)\) For surface…
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