JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
At \(t=0\), a body of mass \(100\) g starts moving under the influence of a force \((5\hat{i}+10\hat{j})\) N. After \(2\) s its position is \((2x\hat{i}+5y\hat{j})\) m. The ratio \(x:y\) is ______.
- A \(1:2\)
- B \(2:5\)
- C \(5:2\)
- D \(5:4\)
Answer & Solution
Correct Answer
(D) \(5:4\)
Step-by-step Solution
Detailed explanation
Mass \(m = 100 \text{ g} = 0.1 \text{ kg}\) Force \(\vec{F} = 5\hat{i} + 10\hat{j} \text{ N}\) Acceleration \(\vec{a} = \dfrac{\vec{F}}{m} = \dfrac{5\hat{i} + 10\hat{j}}{0.1} = 50\hat{i} + 100\hat{j} \text{ m/s}^2\) Since the body starts from rest, initial velocity…
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