JEE Mains · Physics · STD 12 -7. Alternating current
An arc lamp requires a direct current of \(10\ A\) at \(80\ V\) to function. If it is connected to a \( 220\ V (rms ), 50\ Hz\ AC\) supply, the series inductor needed for it to work is close to :
- A \(0.044 \) \(H\)
- B \(0.065\) \( H\)
- C \(80\) \( H\)
- D \(0.08\) \( H\)
Answer & Solution
Correct Answer
(B) \(0.065\) \( H\)
Step-by-step Solution
Detailed explanation
Here \(\mathrm{i}=\frac{\mathrm{e}}{\sqrt{\mathrm{R}^{2}+\mathrm{X}_{\mathrm{L}}^{2}}}=\frac{\mathrm{e}}{\sqrt{\mathrm{R}^{2}+\omega^{2} \mathrm{L}^{2}}}=\frac{\mathrm{e}}{\sqrt{\mathrm{R}^{2}+4 \pi^{2} \mathrm{v}^{2} \mathrm{L}^{2}}}\)…
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