JEE Mains · Physics · STD 12 - 8. Electromagnetic waves
The correct match between the entries in column \(I\) and column \(II\) are \(I\) \((II)\) Radiation Wavelength \((a)\) Microwave \((i)\) \(100 m\) \((b)\) Gamma rays \((ii)\) \(10^{-15} m\) \((c)\) \(A.M.\) radio waves \((iii)\) \(10^{-10} m\) \((d)\) \(X-\)rays \((iv)\) \(10^{-3} m\)
- A \((a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)\)
- B \((a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)\)
- C \((a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)\)
- D \((a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)\)
Answer & Solution
Correct Answer
(D) \((a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)\)
Step-by-step Solution
Detailed explanation
Energes of given Radiation can have The following relation \(E _{\gamma- Rays }> E _{ X - Rays }> E _{ microwave }> E _{ AM }\) Rodiowaves \(\therefore \lambda_{\gamma- Rays }<\lambda_{ X - Rays }<\lambda_{ microwave }<\lambda_{ AM }\) Rodiowaves According To tres. \((a)\)…
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