JEE Mains · Physics · STD 12 - Electromagnetic waves
- JEE Mains 2020
- Medium
- MCQ
The correct match between the entries in column \(I\) and column \(II\) are \(I\) \((II)\) Radiation Wavelength \((a)\) Microwave \((i)\) \(100 m\) \((b)\) Gamma rays \((ii)\) \(10^{-15} m\) \((c)\) \(A.M.\) radio waves \((iii)\) \(10^{-10} m\) \((d)\) \(X-\)rays \((iv)\) \(10^{-3} m\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \((a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)\)
Step-by-step Solution
Detailed explanation
Energes of given Radiation can have
The following relation
\(E _{\gamma- Rays }> E _{ X - Rays }> E _{ microwave }> E _{ AM }\) Rodiowaves
\(\therefore \lambda_{\gamma- Rays }<\lambda_{ X - Rays }<\lambda_{ microwave }<\lambda_{ AM }\) Rodiowaves
According To tres.
\((a)\) Microwave \(\rightarrow 10^{-3} m\) \((iv)\)
\((b)\) Gamma Rays \(\rightarrow 10^{-15} m\) \((ii)\)
\((c)\) \(AM\) Radio wave \(\rightarrow 100 m\) \((i)\)
\((d)\) \(X-\)Rays \(\rightarrow 10^{-10} m\) \((iii)\)
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