JEE Mains · Physics · STD 11 - System of particles and rotational motion
- JEE Mains 2019
- Hard
- MCQ
Two particles \(A, B\) are moving on two concentric circles of radii \(R_1\) and \(R_2\) with equal angular speed \(\omega \). At \(t = 0,\) their positions and direction of motion are shown in the figure The relative velocity \(\overrightarrow {{V_A}} - \overrightarrow {{V_B}} \) at \(t = \frac{\pi }{{2\omega }}\) is given by
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(\omega ({R_2} - {R_1})\,\hat i\)
Step-by-step Solution
Detailed explanation
at \(t= 0\) \(at\,t = \frac{\pi }{{2\omega }}\)
\({\overrightarrow V _A} = {\overrightarrow V _B} = - \omega {R_1}\hat i + \omega .{R_2}\hat i\)
\( = \omega \left( {{R_2} - {R_1}} \right)\hat i\)
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