JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
A wheel is rolling on a plane surface. The speed of a particle on the highest point of the rim is \(8 \mathrm{~m} / \mathrm{s}\). The speed of the particle on the rim of the wheel at the same level as the centre of wheel, will be :
- A \(4 \sqrt{2} \mathrm{~m} / \mathrm{s}\)
- B \(8 \mathrm{~m} / \mathrm{s}\)
- C \(4 \mathrm{~m} / \mathrm{s}\)
- D \(8 \sqrt{2} \mathrm{~m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(A) \(4 \sqrt{2} \mathrm{~m} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
If \(V_B=2 V\) Point A is instantaneous center of rotation Given \(V_B=8 \mathrm{~m} / \mathrm{s}\)…
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