A wheel is rolling on a plane surface. The speed of a particle on the highest point of the rim is 8 m / s. The speed of the particle on the rim of the wheel at the same level as the centre of wheel, will be:

(D) 8 \sqrt{2} \mathrm{~m} / \mathrm{s}

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JEE Mains · Physics · STD 11 - System of particles and rotational motion

JEE Mains 2025
Medium
MCQ

A wheel is rolling on a plane surface. The speed of a particle on the highest point of the rim is \(8 \mathrm{~m} / \mathrm{s}\). The speed of the particle on the rim of the wheel at the same level as the centre of wheel, will be :

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Answer & Solution

Correct Answer

(A) \(4 \sqrt{2} \mathrm{~m} / \mathrm{s}\)

Step-by-step Solution

Detailed explanation

If \(V_B=2 V\)
Point A is instantaneous center of rotation
Given \(V_B=8 \mathrm{~m} / \mathrm{s}\)
\(\begin{aligned}
& \mathrm{V}=4 \mathrm{~m} / \mathrm{s} \\
& \mathrm{~V}_{\mathrm{p}}=\sqrt{2} \mathrm{v} \Rightarrow \mathrm{~V}_{\mathrm{p}}=4 \sqrt{2} \mathrm{~m} / \mathrm{s} \\
& \operatorname{correct}(1)
\end{aligned}\)

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