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JEE Mains · Physics · STD 12 -7. Alternating current
In the below circuit, \(C\, = \,\frac{{\sqrt 3 }}{2}\,\mu F,\,R = 20\,\,\Omega ,\,L = \frac{{\sqrt 3 }}{{10}}H\) and \({R_1} = 10\,\,\Omega .\) Current in \(L-R_1\) path is \(I_1\) and \(C-R_2\) path is \(I_2.\) The voltage of \(A.C\) source is given by, \(V\, = \,200\sqrt 2 \,\sin \,(100\,t)\,volts.\) The phase difference between \(I_1\) and \(I_2\) is
- A \(60^o\)
- B \(30^o\)
- C \(90^o\)
- D None of these
Answer & Solution
Correct Answer
(D) None of these
Step-by-step Solution
Detailed explanation
For the first branch: \( \tan \phi_{1} =\frac{-X_{c}}{R_{2}}=\frac{\frac{1}{\left(100 \times \frac{\sqrt{3}}{2} \times 10^{-6}\right)}}{20} \approx-10^{-3}\) \(\Rightarrow \quad \phi_{1} \approx-90^{\circ}\) For the second branch: \(\tan \phi_{2}=\frac{X_{L}}{R}=\sqrt{3}\)…
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