ExamBro
ExamBro
JEE Mains · Physics · STD 12 - Electromagnetic waves
  • JEE Mains 2022
  • Medium
  • MCQ

The electric field in an electromagnetic wave is given by \(E =56.5 \sin \omega( t - x / c ) \;NC ^{-1}\). Find the intensity of the wave if it is propagating along \(x-\)axis in the free space. (Given \(\left.\varepsilon_{0}=8.85 \times 10^{-12} \;C ^{2} N ^{-1} m ^{-2}\right)\)

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(B) \(4.24 \;Wm ^{-2}\)

Step-by-step Solution

Detailed explanation

\(I =\frac{1}{2} \varepsilon_{0} E _{0}^{2} c\)

\(I =\frac{1}{2} \times\left(8.85 \times 10^{-12}\right)(56.5)^{2} \times\left(3 \times 10^{8}\right)\)

\(=4.24 Wm ^{-2} .\)

Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app