JEE Mains · Physics · STD 11 - Waves and sound
- JEE Mains 2019
- Hard
- Numerical
A tuning fork of frequency \(480\, Hz\) is used in an experiment for measuring speed of sound \((\nu )\) in air by resonance tube method. Resonance is observed to occur at two successive lengths of the air column, \({\ell _1} = 30\,cm\) and \({\ell _2} = 70\,cm\). Then \(\nu\) is equal to ..... \(ms^{-1}\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(384\)
Step-by-step Solution
Detailed explanation
\(v=2 f(l_2-l_1)\)
\(v=2 \times 480 \times(70-30) \times 10^{-2}\)
\(v=960 \times 40 \times 10^{-2}\)
\(\mathrm{v}=38400 \times 10^{-2} \mathrm{m} / \mathrm{s}\)
\(v=384 \mathrm{m} / \mathrm{s}\)
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