JEE Mains · Physics · STD 11 - Gravitation
- JEE Mains 2022
- Hard
- Numerical
A body is projected vertically upwards from the surface of earth with a velocity equal to one third of escape velocity. The maximum height attained by the body will be \(......km\) (Take radius of earth \(=6400\,km\) and \(g =10\,ms^{-2}\) )
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(800\)
Step-by-step Solution
Detailed explanation
\(v _{ e }=\sqrt{\frac{2 Gm }{ R }}\)
\(\frac{- GMm }{ R }+\frac{1}{2} m \frac{ V _{ o }^{2}}{9}=-\frac{ GMm }{ R + h }\)
\(\frac{ GM }{ R + h }=\frac{ GM }{ R }-\frac{ V _{ e }^{2}}{18}\)
\(\frac{ GM }{ R + h }=\frac{ GM }{ R }-\frac{ GM }{9 R }\)
\(\frac{ GM }{ R + h }=\frac{8 GM }{9 R }\)
\(\frac{1}{ R + h }=\frac{8}{9 R }\)
\(9 R =8 R +8 h\)
\(h =\frac{ R }{8} \Rightarrow \frac{6400}{8} \Rightarrow 800 km\)
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