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JEE Mains · Physics · STD 11 - Gravitation
  • JEE Mains 2022
  • Hard
  • Numerical

A body is projected vertically upwards from the surface of earth with a velocity equal to one third of escape velocity. The maximum height attained by the body will be \(......km\) (Take radius of earth \(=6400\,km\) and \(g =10\,ms^{-2}\) )

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Answer & Solution

Correct Answer

(A) \(800\)

Step-by-step Solution

Detailed explanation

\(v _{ e }=\sqrt{\frac{2 Gm }{ R }}\)

\(\frac{- GMm }{ R }+\frac{1}{2} m \frac{ V _{ o }^{2}}{9}=-\frac{ GMm }{ R + h }\)

\(\frac{ GM }{ R + h }=\frac{ GM }{ R }-\frac{ V _{ e }^{2}}{18}\)

\(\frac{ GM }{ R + h }=\frac{ GM }{ R }-\frac{ GM }{9 R }\)

\(\frac{ GM }{ R + h }=\frac{8 GM }{9 R }\)

\(\frac{1}{ R + h }=\frac{8}{9 R }\)

\(9 R =8 R +8 h\)

\(h =\frac{ R }{8} \Rightarrow \frac{6400}{8} \Rightarrow 800 km\)

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