JEE Mains · Physics · STD 11 - Waves and sound
- JEE Mains 2023
- Medium
- Numerical
The fundamental frequency of vibration of a string stretched between two rigid support is \(50\,Hz\). The mass of the string is \(18\,g\) and its linear mass density is \(20\,g / m\). The speed of the transverse waves so produced in the string is \(..........\,ms ^{-1}\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(90\)
Step-by-step Solution
Detailed explanation
Fundamental frequency \(=50\,Hz\)
\(\frac{mass}{length}\)=\(\frac{20 g}{m}\)
mass\(=18\,g\)
length of string \(=\frac{18}{20} m =\frac{9}{10} m\)
from diagram \(\frac{\lambda}{2}=\ell\)
\(\Rightarrow \lambda=2 \ell=\frac{9}{5}\,m\)
again speed \(v=f \lambda=50 \times \frac{9}{5}=90\,m / s\)
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