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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2023
  • Medium
  • Numerical

The fundamental frequency of vibration of a string stretched between two rigid support is \(50\,Hz\). The mass of the string is \(18\,g\) and its linear mass density is \(20\,g / m\). The speed of the transverse waves so produced in the string is \(..........\,ms ^{-1}\)

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Answer & Solution

Correct Answer

(A) \(90\)

Step-by-step Solution

Detailed explanation

Fundamental frequency \(=50\,Hz\)

\(\frac{mass}{length}\)=\(\frac{20 g}{m}\)

mass\(=18\,g\)

length of string \(=\frac{18}{20} m =\frac{9}{10} m\)

from diagram \(\frac{\lambda}{2}=\ell\)

\(\Rightarrow \lambda=2 \ell=\frac{9}{5}\,m\)

again speed \(v=f \lambda=50 \times \frac{9}{5}=90\,m / s\)

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