JEE Mains · Physics · STD 11 - 14. waves and sound
The fundamental frequency of vibration of a string stretched between two rigid support is \(50\,Hz\). The mass of the string is \(18\,g\) and its linear mass density is \(20\,g / m\). The speed of the transverse waves so produced in the string is \(..........\,ms ^{-1}\)
- A \(90\)
- B \(45\)
- C \(30\)
- D \(15\)
Answer & Solution
Correct Answer
(A) \(90\)
Step-by-step Solution
Detailed explanation
Fundamental frequency \(=50\,Hz\) \(\frac{mass}{length}\)=\(\frac{20 g}{m}\) mass\(=18\,g\) length of string \(=\frac{18}{20} m =\frac{9}{10} m\) from diagram \(\frac{\lambda}{2}=\ell\) \(\Rightarrow \lambda=2 \ell=\frac{9}{5}\,m\) again speed…
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