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JEE Mains · Physics · STD 12 -7. Alternating current

The figure given below shows an \(LCR\) series circuit with two switches \(S_1\) and \(S_2\). When switch \(S_1\) is closed keeping \(S_2\) open, the phase difference \((\phi)\) between the current and source voltage is \(30°\) and phase difference is \(60°\) when \(S_2\) is closed keeping \(S_1\) open. The value of \((3L_1 - L_2)\) is _______ H.

  1. A \(\dfrac{9}{2}\)
  2. B \(\dfrac{2}{9}\)
  3. C \(\dfrac{1}{3}\)
  4. D \(3\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\dfrac{2}{9}\)

Step-by-step Solution

Detailed explanation

From the source \(v = V_0 \sin(300t)\), the angular frequency is \(\omega = 300\text{ rad/s}\). Capacitance \(C = 100\ \mu\text{F} = 10^{-4}\text{ F}\), so \(X_C = \dfrac{1}{\omega C}\). Case 1 (\(S_1\) closed, \(S_2\) open): Closing \(S_1\) short-circuits \(L_2\), leaving an…
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