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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2022
  • Medium
  • Numerical

A student in the laboratory measures thickness of a wire using screw gauge. The readings are \(1.22\,mm , 1.23\,mm , 1.19\,mm\) and \(1.20\,mm\). The percentage error is \(\frac{ x }{121} \%\). The value of \(x\) is ..............

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Answer & Solution

Correct Answer

(B) \(150\)

Step-by-step Solution

Detailed explanation

\(X =\frac{1.22 mm +1.23 mm +1.19 mm +1.20 mm }{4}\)

\(X =1.21 mm\)

\(\Delta x =\frac{0.01+0.02+0.02+0.01}{4}=\frac{0.06}{4}=0.015\)

Percentage error \(=\frac{0.015}{1.21} \times 100\)

\(X =150\)

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