JEE Mains · Physics · 14. Kinetic Theory of Gases
A mixture of carbon dioxide and oxygen has volume \(8310\) cm\(^3\), temperature \(300\) K, pressure \(100\) kPa and mass \(13.2\) g. The number of moles of carbon dioxide and oxygen gases in the mixture respectively are _______.
(Assume both carbon dioxide and oxygen gases behave like ideal gases) \([R = 8.31\) J/mol.K\(]\)
- A \(0.15\) and \(0.18\)
- B \(0.25\) and \(0.08\)
- C \(0.21\) and \(0.12\)
- D \(0.13\) and \(0.20\)
Answer & Solution
Correct Answer
(C) \(0.21\) and \(0.12\)
Step-by-step Solution
Detailed explanation
Using the ideal gas equation, the total number of moles of the mixture is given by: \(n = \dfrac{PV}{RT}\) Substituting the given values: \(P = 100 \text{ kPa} = 10^5 \text{ Pa}\) \(V = 8310 \text{ cm}^3 = 8.31 \times 10^{-3} \text{ m}^3\) \(T = 300 \text{ K}\)…
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