JEE Mains · Physics · STD 11- 8. mechanical properties of solids
A string \(A\) of length \(0.314\) m and Young's modulus \(2 \times 10^{10}\) N/m\(^2\) is connected to another string \(B\) of length and Young's modulus both twice of those of \(A\). This series combination of strings is then suspended from a rigid support and its free end is fixed to a load of mass \(0.8\) kg. The net change in length of the combination is _____ mm. (radius of both the strings is \(0.2\) mm and acceleration due to gravity \(= 10\) m/s\(^2\)) (Mass of both strings is to be neglected as compared to the mass of load)
- A \(3\)
- B \(2\)
- C \(1.9\)
- D \(1\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
Given: Length of string A, \(L_A = 0.314\) m Young's modulus of string A, \(Y_A = 2 \times 10^{10}\) N/m\(^2\) Radius of both strings, \(r = 0.2\) mm \(= 2 \times 10^{-4}\) m Length of string B, \(L_B = 2L_A = 0.628\) m Young's modulus of string B,…
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