JEE Mains · Physics · STD 12 - 1. Electric charges and fields
A metallic ring is uniformly charged as shown in figure. AC and BD are two mutually perpendicular diameters. Electric field due to \(\operatorname{arc} \mathrm{AB}\) to ' O ' is ' E ' is magnitude. What would be the magnitude of electric field at ' O ' due to arc ABC ?
- A 2 E
- B \(\sqrt{2} \mathrm{E}\)
- C \(\mathrm{E} / 2\)
- D Zero
Answer & Solution
Correct Answer
(B) \(\sqrt{2} \mathrm{E}\)
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