JEE Mains · Physics · STD 12 - 13. Nuclei
Assume that protons and neutrons have equal masses. Mass of a nucleon is \(1.6 \times 10^{-27}\,kg\) and radius of nucleus is \(1.5 \times 10^{-15} A ^{1 / 3}\,m\). The approximate ratio of the nuclear density and water density is \(n \times 10^{13}\). The value of \(n\) is \(.................\)
- A \(11\)
- B \(12\)
- C \(14\)
- D \(16\)
Answer & Solution
Correct Answer
(A) \(11\)
Step-by-step Solution
Detailed explanation
\(\text { density of nuclei }=\frac{\text { mass of nuclei }}{\text { volume of nuclei }}\) \(\rho=\frac{1.6 \times 10^{-27} A }{\frac{4}{3} \pi\left(1.5 \times 10^{-15}\right)^3 A } \) \(=\frac{1.6 \times 10^{-27}}{14.14 \times 10^{-45}}=0.113 \times 10^{18}\)…
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