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JEE Mains · Physics · STD 12 - Nuclei
  • JEE Mains 2023
  • Medium
  • Numerical

Assume that protons and neutrons have equal masses. Mass of a nucleon is \(1.6 \times 10^{-27}\,kg\) and radius of nucleus is \(1.5 \times 10^{-15} A ^{1 / 3}\,m\). The approximate ratio of the nuclear density and water density is \(n \times 10^{13}\). The value of \(n\) is \(.................\)

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Answer & Solution

Correct Answer

(A) \(11\)

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Detailed explanation

\(\text { density of nuclei }=\frac{\text { mass of nuclei }}{\text { volume of nuclei }}\)

\(\rho=\frac{1.6 \times 10^{-27} A }{\frac{4}{3} \pi\left(1.5 \times 10^{-15}\right)^3 A } \)

\(=\frac{1.6 \times 10^{-27}}{14.14 \times 10^{-45}}=0.113 \times 10^{18}\)

\(\rho_{ W }=10^3\)

\(\text { Hence } \frac{\rho}{\rho_w}=11.31 \times 10^{13}\)

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