JEE Mains · Physics · STD 11- 8. mechanical properties of solids
A steel rod has a radius of \(20\,mm\) and a length of \(2.0\,m\). A force of \(62.8\,kN\) stretches it along its length. Young's modulus of steel is \(2.0 \times 10^{11}\,N / m ^2\). The longitudinal strain produced in the wire is \(..........\times 10^{-5}\)
- A \(24\)
- B \(23\)
- C \(22\)
- D \(25\)
Answer & Solution
Correct Answer
(D) \(25\)
Step-by-step Solution
Detailed explanation
\(\text {Strain}=\frac{\text { stress }}{Y}=\frac{\frac{62.8 \times 10^3}{\pi \times(0.02)^2}}{2 \times 10^{11}}\) \(=\frac{62.8 \times 10^3}{3.14 \times 4 \times 10^{-4} \times 2 \times 10^{11}}\) \(=2.5 \times 10^{-4}\) \(=25 \times 10^{-5}\)
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