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JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement

The energy of a system is given as \(\mathrm{E}(\mathrm{t})=\alpha^3 \mathrm{e}^{-\beta t}\), where t is the time and \(\beta=0.3 \mathrm{~s}^{-1}\). The errors in the measurement of \(\alpha\) and \(t\) are \(1.2 \%\) and \(1.6 \%\), respectively. At \(t=5 \mathrm{~s}\), maximum percentage error in the energy is :

  1. A \(6 \%\)
  2. B \(8.4 \%\)
  3. C \(11.6 \%\)
  4. D \(4 \%\)
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Answer & Solution

Correct Answer

(A) \(6 \%\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & d E=3 \alpha^2 d \alpha e^{-\beta t}+\alpha^3 e^{-\beta t}(-\beta) d t \\ & \frac{d E}{E}=\frac{3 d \alpha}{\alpha}+(-\beta) d t \\ & \frac{\Delta E}{E}=\frac{3 \Delta \alpha}{\alpha}+\beta \Delta t \end{aligned}\) (\%) \(\Delta t=1.6 \% \times 5=8 \%\)…
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