JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
Figure shows a network of capacitors where the numbers indicates capacitances in micro Farad. The value of capacitance \(C\) if the equivalent capacitance between point \(A\) and \(B\) is to be \(1\,\mu F\) is
- A \(\frac{{32}}{{23}}\,\mu F\)
- B \(\frac{{31}}{{23}}\,\mu F\)
- C \(\frac{{33}}{{23}}\,\mu F\)
- D \(\frac{{34}}{{23}}\,\mu F\)
Answer & Solution
Correct Answer
(A) \(\frac{{32}}{{23}}\,\mu F\)
Step-by-step Solution
Detailed explanation
Capacitors \(2\, \mu \mathrm{F}\) and \(2\, \mu \mathrm{F}\) are parallel, their equivalent \(=4\, \mu \mathrm{F}\) \(6 \,\mu \mathrm{F}\) and \(12\, \mu \mathrm{F}\) are in series, their equivalent \(=4\, \mu \mathrm{F}\) Now \(4 \,\mu F(2 \text { and } 2\, \mu F)\) and…
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