JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
An \(n.p.n\) transistor with current gain \(\beta=100\) in common emitter configuration is shown in figure. The output voltage of the amplifier will be\(.....V\)
- A \(0.1\)
- B \(1.0\)
- C \(10\)
- D \(100\)
Answer & Solution
Correct Answer
(B) \(1.0\)
Step-by-step Solution
Detailed explanation
\(\frac{v_{\text {out }}}{v_{\text {in }}}=\beta \frac{R_{\text {out }}}{R_{\text {in }}}\) \(v_{\text {out }}=\frac{100 \times 10 \times 10^{3}}{10^{3}} \times 10^{-3}\) \(=1\,V\)
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