JEE Mains · Physics · STD 12 - Semicondutor electronics
- JEE Mains 2022
- Medium
- MCQ
An \(n.p.n\) transistor with current gain \(\beta=100\) in common emitter configuration is shown in figure. The output voltage of the amplifier will be\(.....V\)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(1.0\)
Step-by-step Solution
Detailed explanation
\(\frac{v_{\text {out }}}{v_{\text {in }}}=\beta \frac{R_{\text {out }}}{R_{\text {in }}}\)
\(v_{\text {out }}=\frac{100 \times 10 \times 10^{3}}{10^{3}} \times 10^{-3}\)
\(=1\,V\)
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