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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2022
  • Medium
  • MCQ

An \(n.p.n\) transistor with current gain \(\beta=100\) in common emitter configuration is shown in figure. The output voltage of the amplifier will be\(.....V\)

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Answer & Solution

Correct Answer

(B) \(1.0\)

Step-by-step Solution

Detailed explanation

\(\frac{v_{\text {out }}}{v_{\text {in }}}=\beta \frac{R_{\text {out }}}{R_{\text {in }}}\)

\(v_{\text {out }}=\frac{100 \times 10 \times 10^{3}}{10^{3}} \times 10^{-3}\)

\(=1\,V\)

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