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JEE Mains · Physics · STD 12 -Electromagnetic induction
  • JEE Mains 2024
  • Hard
  • MCQ

A square loop of side \(15 \mathrm{~cm}\) being moved towards right at a constant speed of \(2 \mathrm{~cm} / \mathrm{s}\) as shown in figure. The front edge enters the \(50 \mathrm{~cm}\) wide magnetic field at \(t=0\). The value of induced emf in the loop at \(t=10 \mathrm{~s}\) will be _______.

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Verified Solution

Answer & Solution

Correct Answer

(C) zero

Step-by-step Solution

Detailed explanation

At \(\mathrm{t}=10 \mathrm{sec}\) complete loop is in magnetic field therefore no change in flux

(Image)

\(e=\frac{d \phi}{d t}=0 \)

\(e=0\) for complete loop

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