JEE Mains · Physics · STD 12 -6. Electromagnetic induction
A square loop of side \(15 \mathrm{~cm}\) being moved towards right at a constant speed of \(2 \mathrm{~cm} / \mathrm{s}\) as shown in figure. The front edge enters the \(50 \mathrm{~cm}\) wide magnetic field at \(t=0\). The value of induced emf in the loop at \(t=10 \mathrm{~s}\) will be _______.
- A \(0.3 \mathrm{mV}\)
- B \(4.5 \mathrm{mV}\)
- C zero
- D \(3 \mathrm{mV}\)
Answer & Solution
Correct Answer
(C) zero
Step-by-step Solution
Detailed explanation
At \(\mathrm{t}=10 \mathrm{sec}\) complete loop is in magnetic field therefore no change in flux (Image) \(e=\frac{d \phi}{d t}=0 \) \(e=0\) for complete loop
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