JEE Mains · Physics · STD 12 - Electromagnetic waves
- JEE Mains 2026
- Easy
- MCQ
A point light source emits E.M. waves in free space. A detector, placed at a distance of \(L\) m, measures the intensity as \(I_o\). The detector is now shifted to another location on the same spherical surface ensuring the angle between original location and new location as \(45°\). The measured intensity at new location will be _______.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(I_o\)
Step-by-step Solution
Detailed explanation
For a point light source, the intensity of electromagnetic waves at a distance \(r\) is given by \(I = \dfrac{P}{4\pi r^2}\), where \(P\) is the power of the source.
Since the detector is moved to a new location on the same spherical surface, the distance from the source remains \(L\).
The emission from a point source is isotropic, meaning the intensity depends only on the radial distance from the source and is independent of the angular position.
Therefore, the intensity at the new location remains unchanged, which is \(I_o\).
Answer: \(I_o\)
Since the detector is moved to a new location on the same spherical surface, the distance from the source remains \(L\).
The emission from a point source is isotropic, meaning the intensity depends only on the radial distance from the source and is independent of the angular position.
Therefore, the intensity at the new location remains unchanged, which is \(I_o\).
Answer: \(I_o\)
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