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JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism

A square loop is carrying a steady current \(I\) and the magnitude of its magnetic dipole moment is \(m\). If this square loop is changed to a circular loop and it carries the same current, the magnitude of the magnetic dipole moment of circular loop will be

  1. A \(\frac {m}{\pi }\)
  2. B \(\frac {3m}{\pi }\)
  3. C \(\frac {4m}{\pi }\)
  4. D \(\frac {2m}{\pi }\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac {4m}{\pi }\)

Step-by-step Solution

Detailed explanation

\(m = I{l^2}\) \(2\pi r = 4l\) \({{{\text{m}}^\prime } = \frac{{I4{\ell ^2}}}{\pi }}\) \({{\text{r}} = \frac{{2\ell }}{\pi }}\) \({{{\text{m}}^\prime } = \frac{{I4{\ell ^2}}}{\pi }}\) \({\pi {r^2} = \frac{{\pi 4{\ell ^2}}}{{{\pi ^2}}} = \frac{{4{\ell ^2}}}{\pi }}\)…
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