JEE Mains · Physics · STD 11 - Waves and sound
- JEE Mains 2021
- Easy
- Numerical
A source and a detector move away from each other in absence of wind with a speed of \(20\, {m} / {s}\) with respect to the ground. If the detector detects a frequency of \(1800\, {Hz}\) of the sound coming from the source, then the original frequency of source considering speed of sound in air \(340\, {m} / {s}\) will be \({Hz}\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(2025\)
Step-by-step Solution
Detailed explanation
\({V}_{{S}}=20 {m} / {s} \quad {V}_{{O}}=20 {m} / {s}\)
\({f}^{\prime}={f}\left(\frac{{V}-{V}_{0}}{{V}+{V}_{{s}}}\right)\)
\(1800={f}\left(\frac{340-20}{340+20}\right)\)
\({f}=2025 {Hz}\)
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