JEE Mains · Physics · STD 12 - 8. Electromagnetic waves
Intensity of sunlight is observed as \(0.092\, {Wm}^{-2}\) at a point in free space. What will be the peak value of magnetic field at that point? \(\left(\sigma_{0}=8.85 \times 10^{-12}\, {C}^{2} \,{N}^{-1} \,{m}^{-2}\right.\) )
- A \(8.31\, {T}\)
- B \(5.88 \,{T}\)
- C \(1.96 \,\times 10^{-8} {T}\)
- D \(2.77 \,\times 10^{-8} {T}\)
Answer & Solution
Correct Answer
(D) \(2.77 \,\times 10^{-8} {T}\)
Step-by-step Solution
Detailed explanation
\(I_{\text {avg }}=\frac{B_{0}^{2} C}{2 \mu_{0}} \& \frac{1}{\mu_{0}}=\epsilon_{0} C^{2}\) \(I=\frac{B_{0}^{2}}{2} \in_{0} C^{3}\) \(B_{0}=\sqrt{\frac{2 I}{\epsilon_{0} C^{3}}}\) \(B_{0}=2.77 \times 10^{-8}\, {T}\)
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