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JEE Mains · Physics · STD 11 - Fluid mechanics
  • JEE Mains 2014
  • Hard
  • MCQ

There is a circular tube in a vertical plane. Two liquids which do not mix and of densities \(d_1\) and \(d_2\) are filled in the tube. Each liquid subtends \(90^o\) angle at centre. Radius joining their interface makes an angle \(\alpha\) with vertical. Ratio \(\frac{{{d_1}}}{{{d_2}}}\) is

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Answer & Solution

Correct Answer

(B) \(\;\frac{{1 + tan\alpha }}{{1 - tan\alpha }}\)

Step-by-step Solution

Detailed explanation

Equating pressure at \(A\)

\(\left( {R\cos \alpha  + R\sin \alpha } \right){d_2}g = \left( {R\cos \alpha  - R\sin \alpha } \right){d_1}g\)

\( \Rightarrow \frac{{{d_1}}}{{{d_2}}} = \frac{{\cos \alpha  + \sin \alpha }}{{\cos \alpha  - \sin \alpha }} = \frac{{1 + \tan \alpha }}{{1 - \tan \alpha }}\)

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