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JEE Mains · Physics · STD 11 - 9.1 fluid mechanics

There is a circular tube in a vertical plane. Two liquids which do not mix and of densities \(d_1\) and \(d_2\) are filled in the tube. Each liquid subtends \(90^o\) angle at centre. Radius joining their interface makes an angle \(\alpha\) with vertical. Ratio \(\frac{{{d_1}}}{{{d_2}}}\) is

  1. A \(\frac{{1 + cos\alpha }}{{1 - cos\alpha }}\)
  2. B \(\;\frac{{1 + tan\alpha }}{{1 - tan\alpha }}\)
  3. C \(\;\frac{{1 + sin\alpha }}{{1 - cos\alpha }}\)
  4. D \(\;\frac{{1 + sin\alpha }}{{1 - sin\alpha }}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\;\frac{{1 + tan\alpha }}{{1 - tan\alpha }}\)

Step-by-step Solution

Detailed explanation

Equating pressure at \(A\) \(\left( {R\cos \alpha + R\sin \alpha } \right){d_2}g = \left( {R\cos \alpha - R\sin \alpha } \right){d_1}g\)…
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