JEE Mains · Physics · STD 11 - System of particles and rotational motion
- JEE Mains 2019
- Hard
- MCQ
The following bodies are made to roll up (without slipping) the same inclined plane from a horizontal place: \((i)\) a ring of radius \(R,\,(ii)\) a solid cylinder of radius \(\frac {R}{2}\) nd \((iii)\) a solid sphere of radius \(\frac {R}{4}.\) If, in each case, the speed of the center of mass at bottom of the incline is same, the ratio of the maximum heights they climb is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(14: 15: 20\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{2}\left( {m + \frac{1}{{{R^2}}}} \right){v^2} = mgh\)
If radius of gyration is, then
\(h = \frac{{\left( {1 + \frac{{{k^2}}}{{{R^2}}}} \right)}}{{2g}};\frac{{{k_{ring}}}}{{{R_{ring}}}} = 1,\frac{{{k_{solid\,cylinder}}}}{{{R_{solid\,cylinder}}}} = \frac{1}{{\sqrt 2 }}\)
\(\frac{{{k_{solid\,sphere}}}}{{{R_{solid\,sphere}}}} = \sqrt {\frac{2}{5}} \)
\({H_1}\,:\,{h_2}\,:\,{h_3}\,::\left( {1 + 1} \right)\,:\,\left( {1 + \frac{1}{2}} \right):\left( {1 + \frac{2}{5}} \right)::20\,:\,15\,:\,14\)
Therefore most appropriate option is \((B)\)
Although which is not in correct sequence.
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