List - IList - II(A) Heat capacity of body(I) J kg-1(B) Specific heat capacity of body(II) JK-1(C) Latent heat(III) J kg-1 K-1(D) Thermal conductivity(IV) Jm-1 K-1 s-1Choose the correct answer from the options given below:

(A) (A)-(III), (B)-(I), (C)-(II), (D)-(IV)

(B) (A)-(IV), (B)-(III), (C)-(II), (D)-(I)

(C) (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

enEnglishhiहिन्दी guગુજરાતી

JEE Mains · Physics · STD 11 - Units,dimensions and measurement

JEE Mains 2025
Hard
MCQ

List - I List - II
(A) Heat capacity of body \(\text{(I) } \mathrm{J} \mathrm{kg}^{-1}\)
(B) Specific heat capacity of body \(\text{(II) } \mathrm{JK}^{-1}\)
(C) Latent heat \(\text{(III) } \mathrm{J} \mathrm{kg}^{-1} \mathrm{~K}^{-1}\)
(D) Thermal conductivity \(\text{(IV) } \mathrm{Jm}^{-1} \mathrm{~K}^{-1} \mathrm{~s}^{-1}\)
Choose the correct answer from the options given below:

Pick an option to check your answer.

Verified Solution

Answer & Solution

Correct Answer

(D) (A)-(II), (B)-(III), (C)-(I), (D)-(IV)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \mathrm{C}^{\prime}=\frac{\Delta \mathrm{Q}}{\Delta \mathrm{T}}=\mathrm{JK}^{-1} \\ & \mathrm{~S}=\frac{\Delta \mathrm{Q}}{\mathrm{m} \Delta \mathrm{T}}=\mathrm{Jkg}^{-1} \mathrm{~K}^{-1} \\ & \mathrm{~L}=\frac{\Delta \mathrm{Q}}{\mathrm{m}}=\mathrm{Jkg}^{-1} \\ & \Delta \mathrm{Q}=\frac{\mathrm{KA} \Delta \mathrm{T}}{\mathrm{L}} \Rightarrow \mathrm{K}=\frac{\Delta \mathrm{Q}(\mathrm{L})}{\mathrm{A} \Delta \mathrm{T}}=\mathrm{Jm}^{-1} \mathrm{~K}^{-1} \mathrm{~s}^{-1}\end{aligned}\)

Same subject

Explore more questions on app

From JEE Mains

Explore more questions on app

List - I	List - II
(A) Heat capacity of body	\(\text{(I) } \mathrm{J} \mathrm{kg}^{-1}\)
(B) Specific heat capacity of body	\(\text{(II) } \mathrm{JK}^{-1}\)
(C) Latent heat	\(\text{(III) } \mathrm{J} \mathrm{kg}^{-1} \mathrm{~K}^{-1}\)
(D) Thermal conductivity	\(\text{(IV) } \mathrm{Jm}^{-1} \mathrm{~K}^{-1} \mathrm{~s}^{-1}\)