JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2024
- Hard
- MCQ
Wheatstone bridge principle is used to measure the specific resistance \(\left(S_1\right)\) of given wire, having length \(L\), radius \(r\). If \(X\) is the resistance of wire, then specific resistance is: \(S_1=X\left(\frac{\pi r^2}{L}\right)\). If the length of the wire gets doubled then the value of specific resistance will be :
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(S_1\)
Step-by-step Solution
Detailed explanation
As specific resistance does not depends on dimension of wire so, it will not change.
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