JEE Mains · Physics · STD 12 - 3. current electricity
Wheatstone bridge principle is used to measure the specific resistance \(\left(S_1\right)\) of given wire, having length \(L\), radius \(r\). If \(X\) is the resistance of wire, then specific resistance is: \(S_1=X\left(\frac{\pi r^2}{L}\right)\). If the length of the wire gets doubled then the value of specific resistance will be :
- A \(\frac{S_1}{4}\)
- B \(2 \mathrm{~S}_1\)
- C \(\frac{S_1}{2}\)
- D \(S_1\)
Answer & Solution
Correct Answer
(D) \(S_1\)
Step-by-step Solution
Detailed explanation
As specific resistance does not depends on dimension of wire so, it will not change.
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