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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2026
  • Medium
  • Numerical

The size of the images of an object, formed by a thin lens are equal when the object is placed at two different positions 8 cm and 24 cm from the lens. The focal length of the lens is ___________ cm.

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Answer & Solution

Correct Answer

(B) 16

Step-by-step Solution

Detailed explanation

\(m=\frac{f}{f+u}\)
\(m _1=- m _2\)
\(\frac{f}{f-8}=-\frac{f}{f-24}\)
\(f-8=24-f\)
\(2 f=32\)
\(f =16 cm\)
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