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JEE Mains · Physics · STD 12 - Electric potential and capacitance
  • JEE Mains 2021
  • Medium
  • Numerical

The circuit shown in the figure consists of a charged capacitor of capacity \(3\, \mu F\) and a charge of \(30\, \mu C\). At time \(t =0,\) when the key is closed, the value of current flowing through the \(5\, M \Omega\) resistor is \('x'\) \(\mu-A\). The value of \('x'\) to the nearest integer is .........

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Answer & Solution

Correct Answer

(B) \(2\)

Step-by-step Solution

Detailed explanation

\(i _{0}=\frac{ V }{ R }=\frac{30 / 3}{5 \times 10^{6}}=2 \times 10^{-6}\)

\(\therefore\) Ans. \(=2.00\)

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