JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
The circuit shown in the figure consists of a charged capacitor of capacity \(3\, \mu F\) and a charge of \(30\, \mu C\). At time \(t =0,\) when the key is closed, the value of current flowing through the \(5\, M \Omega\) resistor is \('x'\) \(\mu-A\). The value of \('x'\) to the nearest integer is .........
- A \(1\)
- B \(2\)
- C \(0\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
\(i _{0}=\frac{ V }{ R }=\frac{30 / 3}{5 \times 10^{6}}=2 \times 10^{-6}\) \(\therefore\) Ans. \(=2.00\)
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