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JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement

A screw gauge has \(50\) divisions on its circular scale. The circular scale is \(4\) units ahead of the pitch scale marking, prior to use. Upon one complete rotation of the circular scale, a displacement of \(0.5\, mm\) is noticed on the pitch scale. The nature of zero error involved, and the least count of the screw gauge, are respectively

  1. A Negative, \(2\, \mu m\)
  2. B Positive, \(10\, \mu m\)
  3. C Positive, \(0.1\) \(\mu m\)
  4. D Positive, \(0.1\) \(mm\)
Verified Solution

Answer & Solution

Correct Answer

(B) Positive, \(10\, \mu m\)

Step-by-step Solution

Detailed explanation

Least count of screw gauge \(=\frac{\text { Pitch }}{\text { no. of division on circular scale }}\) \(=\frac{0.5}{50} mm =1 \times 10^{-5} m\) \(=10\, \mu m\) Zero error in positive
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