JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
A \(72 \; \Omega\) galvanometer is shunted by a resistance of \(8 \; \Omega\). The percentage of the total current which passes through the galvanometer is \(.....\)
- A \(0.1\)
- B \(10\)
- C \(25\)
- D \(0.25\)
Answer & Solution
Correct Answer
(B) \(10\)
Step-by-step Solution
Detailed explanation
\(S=\frac{R_{G}}{\frac{I}{I_{g}}-1}\) \(8=\frac{72}{\frac{I}{I_{g}}-1}\) \(\frac{I}{I_{g}}-1=9\) \(\frac{I}{I_{g}}=10 \Rightarrow \frac{I_{g}}{I}=\frac{1}{10} \quad \% I=\frac{I_{g}}{I} \times 100=10 \%\)
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