JEE Mains · Physics · STD 12 -Alternating current
- JEE Mains 2024
- Hard
- MCQ
A series \(LR\) circuit connected with an ac source \(E=(25 \sin 1000 t)\ V\) has a power factor of \(\frac{1}{\sqrt{2}}\). If the source of emf is changed to \(E=(20 \sin 2000 t)\ V,\) the new power factor of the circuit will be _______.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(\frac{1}{\sqrt{5}}\)
Step-by-step Solution
Detailed explanation
\( E=25 \sin (1000 t) \)
\( \cos \theta=\frac{1}{\sqrt{2}}\)
LR circuit
\( \text { Initially } \frac{R}{\omega_1 L}=\frac{1}{\tan \theta}=\frac{1}{\tan 45^{\circ}}= \)
\( X_L=\omega_1 L \)
\( \omega_2=2 \omega_1 \text {, given } \)
\( \tan \theta^{\prime}=\frac{\omega_2 L}{R}=\frac{2 \omega_1 L}{R} \)
\( \tan \theta^{\prime}=2 \)
\( \cos \theta^{\prime}=\frac{1}{\sqrt{5}}\)
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