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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2022
  • Hard
  • MCQ

A screw gauge of pitch \(0.5\,mm\) is used to measure the diameter of uniform wire of length \(6.8\,cm\), the main scale reading is \(1.5\,mm\) and circular scale reading is \(7\). The calculated curved surface area of wire to appropriate significant figures is \(......cm^2\) . [Screw gauge has \(50\) divisions on the circular scale]

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Answer & Solution

Correct Answer

(B) \(3.4\)

Step-by-step Solution

Detailed explanation

\( L.C.=\frac{P}{N}=\frac{0.5\,mm}{50}=0.01\,mm\)

Length of wire \(=6.8 cm\)

Diameter of wire \(=1.5\,mm +7 \times L.C\)

\(=1.5\, mm +7 \times .01=1.57\,mm\)

Curved surface area \(=\pi Dl\)

\(=3.14 \times 6.8 \times 1.57 \times 10^{-1} cm^{2}\)

\(=3.352\,cm ^{2}=3.4\,cm ^{2}\)

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