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JEE Mains · Physics · STD 11 - Waves and sound
- JEE Mains 2013
- Hard
- Numerical
When two sound waves travel in the same direction in a medium, the displacements of a particle located at \('x'\) at time \('t'\) is given by \({y_1} = 0.05\,\cos \,\left( {0.50\,\pi x - 100\,\pi t} \right)\) \({y_2} = 0.05\,\cos \,\left( {0.46\,\pi x - 92\,\pi t} \right)\) then velocity is..... \(m/s\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(200\)
Step-by-step Solution
Detailed explanation
Standard equation
\(\mathrm{y}(\mathrm{x}, \mathrm{t})=\mathrm{A} \cos \left(\frac{\omega}{\mathrm{V}} \mathrm{x}-\omega \mathrm{t}\right)\)
From any of the displacement equation Say \(y_1\)
\(\frac{\omega}{V}=0.50 \pi \text { and } \omega=100 \pi\)
\(\therefore \frac{100 \pi}{V}=0.5 \pi\)
\(\therefore \mathrm{V}=\frac{100 \pi}{0.5 \pi}=200 \mathrm{m} / \mathrm{s}\)
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