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JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments

The radius of curvature for a thin convex lens are 10 cm and 15 cm respectively. The focal length of the lens is 12 cm. The refractive index of the lens material is :

  1. A 1.2
  2. B 1.4
  3. C 1.5
  4. D 1.8
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Answer & Solution

Correct Answer

(C) 1.5

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \frac{1}{\mathrm{f}}=(\mu-1)\left(\frac{1}{\mathrm{R}_1}-\frac{1}{\mathrm{R}_2}\right) \\ & \frac{1}{12}=(\mu-1)\left(\frac{1}{10}-\frac{1}{-15}\right) \\ & \frac{1}{12}=(\mu-1)\left(\frac{3+2}{30}\right) \\ & \mu=\frac{3}{2}\end{aligned}\)
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