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JEE Mains · Maths · STD 12 - 7.2 definite integral

Let \([ x ]\) denote the greatest integer \(\leq x\). Consider the function \(f(x)=\max \left\{x^2, 1+[x]\right\}\). Then the value of the integral \(\int \limits_0^2 f ( x ) dx\) is :

  1. A \(\frac{5+4 \sqrt{2}}{3}\)
  2. B \(\frac{8+4 \sqrt{2}}{3}\)
  3. C \(\frac{1+5 \sqrt{2}}{3}\)
  4. D \(\frac{4+5 \sqrt{2}}{3}\)
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Answer & Solution

Correct Answer

(A) \(\frac{5+4 \sqrt{2}}{3}\)

Step-by-step Solution

Detailed explanation

\(A=\int \limits_0^1 1 . d x+\int \limits_1^{\sqrt{2}} 2 d x+\int \limits_{\sqrt{2}}^2 x^2 d x\) \(=1+2 \sqrt{2}-2+\frac{8}{3}-\frac{2 \sqrt{2}}{3}\) \(=\frac{5}{3}+\frac{4 \sqrt{2}}{3}\)
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