JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
The magnitude of the magnetic field at the centre of an equilateral triangular loop of side \(1\,m\) which is carrying a current of \(10\,A\) is:......\(\mu T\) [Take \(\mu _0 = 4\pi \times 10^{-7}\,NA^{-2}\)]
- A \(9\)
- B \(1\)
- C \(3\)
- D \(18\)
Answer & Solution
Correct Answer
(C) \(3\)
Step-by-step Solution
Detailed explanation
\(i=10\, \mathrm{A}\) \(\ell=1\, \mathrm{m}\) \(\mu_{0}=4 \pi \times 10^{-7} \,\frac{\mathrm{N}}{\mathrm{A}^{2}}\) \(\mathrm{B}=\frac{\mu_{0} \mathrm{i}}{\frac{4 \pi \sqrt{3} \ell}{2}} \times 3\)…
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