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JEE Mains · Physics · STD 11 - 5. work,energy,power and collision

A particle is moving in a circular path of radius a under the action of an attractive potential \(U = - \frac{k}{{2{r^2}}}\) Its total energy is

  1. A \(\;\frac{k}{{2{a^2}}}\)
  2. B Zero
  3. C \( - \frac{3}{2}\;\frac{k}{{{a^2}}}\)
  4. D \( - \frac{k}{{4{a^2}}}\)
Verified Solution

Answer & Solution

Correct Answer

(B) Zero

Step-by-step Solution

Detailed explanation

\(F = \frac{{\partial u}}{{\partial r}}\,\hat r = \frac{K}{{{r^3}}}\,\hat r\) Since particle is moving in circular path…
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