JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
Potential energy (V) versus distance (x) is given by the graph, Rank various regions as per the magnitudes of the force (F) acting on a particle from high to low.
- A \(F _{ BC }> F _{ CD }> F _{ DE }> F _{ AB }\)
- B \(F _{ CD }> F _{ AB }> F _{ BC }> F _{ DE }\)
- C \(F _{ CD }> F _{ DE }> F _{ AB }> F _{ BC }\)
- D \(F _{ BC }> F _{ AB }> F _{ DE }> F _{ CD }\)
Answer & Solution
Correct Answer
(D) \(F _{ BC }> F _{ AB }> F _{ DE }> F _{ CD }\)
Step-by-step Solution
Detailed explanation
Slope of potential energy \(v / s\) position curve gives negative of force. \(\therefore \quad F _{ BC }> F _{ AB }> F _{ DE }> F _{ CD }\)
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