JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
In a collinear collision, a particle with an initial speed \(v_0\) strikes a stationary particle of the same mass. If the final total kinetic energy is \(50\%\) greater than the original kinetic energy, the magnitude of the relative velocity between the two particles, after collision, is:
- A \(\sqrt 2 \;{v_0}\)
- B \(\frac{{{v_0}}}{2}\)
- C \(\;\frac{{{v_0}}}{{\sqrt 2 }}\)
- D \(\frac{{{v_0}}}{4}\)
Answer & Solution
Correct Answer
(A) \(\sqrt 2 \;{v_0}\)
Step-by-step Solution
Detailed explanation
Before collision after collision…
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