JEE Mains · Physics · STD 11 - 2. motion in straight line
Two spherical balls having equal masses with radius of \(5\, {cm}\) each are thrown upwards along the same vertical direction at an interval of \(3\, {s}\) with the same initial velocity of \(35 \,{m} / {s}\), then these balls collide at a height of \(\ldots \ldots \ldots . {m}\). (Take \({g}=10 \,{m} / {s}^{2}\) )
- A \(80\)
- B \(10\)
- C \(60\)
- D \(50\)
Answer & Solution
Correct Answer
(D) \(50\)
Step-by-step Solution
Detailed explanation
When both balls will collied \({y}_{1}={y}_{2}\) \(35 {t}-\frac{1}{2} \times 10 \times {t}^{2}=35({t}-3)-\frac{1}{2} \times 10 \times({t}-3)^{2}\) \(35 {t}-\frac{1}{2} \times 10 \times {t}^{2}=35 {t}-105-\frac{1}{2} \times 10 \times {t}^{2}\)…
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