JEE Mains · Physics · STD 12 - Electric potential and capacitance
- JEE Mains 2026
- Easy
- MCQ
A point charge of \(10^{-8} C\) is placed at origin. The work done in moving a point charge \(2 \mu C\) from point \(A (4,4,2) m\) to \(B (2,2,1) m\) is _________ J.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(30 \times 10^{-6}\)
Step-by-step Solution
Detailed explanation
Work done by external agent :
\(W _{ ext }=\Delta U ;\)
\(\Delta U \rightarrow\) Change in potential energy in taking the charge from initial to final configuration
\(\Rightarrow W _{ ext }=\frac{1}{4 \pi \epsilon_0} \frac{ q _1 q _2}{ r _{ f }}-\frac{1}{4 \pi \epsilon_0} \frac{ q _1 q _2}{ r _{ i }}\)
Now, \(r_f=\sqrt{(2-0)^2+(2-0)^2+(1-0)^2}=3 m\)
\(r_i=\sqrt{(4-0)^2+(4-0)^2+(2-0)^2}=6 m\)
\(\therefore \quad W _{\text {ext }}=\left(9 \times 10^9\right) \times\left(10^{-8} \times 2 \times 10^{-6}\right)\left[\frac{1}{3}-\frac{1}{6}\right]\)
\(=3 \times 10^{-5}\)
\(=30 \times 10^{-6} J\)
\(W _{ ext }=\Delta U ;\)
\(\Delta U \rightarrow\) Change in potential energy in taking the charge from initial to final configuration
\(\Rightarrow W _{ ext }=\frac{1}{4 \pi \epsilon_0} \frac{ q _1 q _2}{ r _{ f }}-\frac{1}{4 \pi \epsilon_0} \frac{ q _1 q _2}{ r _{ i }}\)
Now, \(r_f=\sqrt{(2-0)^2+(2-0)^2+(1-0)^2}=3 m\)
\(r_i=\sqrt{(4-0)^2+(4-0)^2+(2-0)^2}=6 m\)
\(\therefore \quad W _{\text {ext }}=\left(9 \times 10^9\right) \times\left(10^{-8} \times 2 \times 10^{-6}\right)\left[\frac{1}{3}-\frac{1}{6}\right]\)
\(=3 \times 10^{-5}\)
\(=30 \times 10^{-6} J\)
More questions from Physics
- Two small equal point charges of magnitude \(q\) are suspended from a common point on the ceiling by insulating mass less strings of equal lengths. They come to equilibrium with each string making angle \(\theta \) from the vertical. If the mass of each charge is \(m,\) then the electrostatic potential at the centre of line joining them will be \(\left( {\frac{1}{{4\pi { \in _0}}} = k} \right).\)JEE Mains 2013 Hard
- Surface tension of a soap bubble is \(2.0 \times 10^{-2}\; Nm ^{-1}\). Work done to increase the radius of soap bubble from \(3.5\; cm\) to \(7\; cm\) will be \(.........\times 10^{-4}\,J\) [Take \(\pi=\frac{22}{7}\) ]JEE Mains 2023 Medium
- Statement \(I :\) The ferromagnetic property depends on temperature. At high temperature, ferromagnet becomes paramagnet. Statement \(II :\) At high temperature, the domain wall area of a ferromagnetic substance increases. In the light of the above statements, choose the most appropriate answer from the options given below :JEE Mains 2021 Medium
- A simple pendulum doing small oscillations at a place \(\mathrm{R}\) height above earth surface has time period of \(T_1=4 \mathrm{~s}\). \(T_2\) would be it's time period if it is brought to a point which is at a height \(2 R\) from earth surface. Choose the correct relation. \([R=\) radius of Earth]:JEE Mains 2024 Hard
- A current loop, having two circular arcs joined by two radial lines is shown in the figure. It carries a current of \(10\, A\). The magnetic field at point \(O\) will be close to
JEE Mains 2019 Medium - A light planet is revolving around a massive star in a circular orbit of radius \(R\) with a period of revolution \(T\). If the force of attraction between planet and star is proportional to \(\mathrm{R}^{-3 / 2}\) then choose the correct option.JEE Mains 2024 Hard
More PYQs from JEE Mains
- As shown in the figure, a current of \(2\,A\) flowing in an equilateral triangle of side \(4 \sqrt{3}\,cm\). The magnetic field at the centroid \(O\) of the triangle is: (Neglect the effect of earth's magnetic field.)
JEE Mains 2023 Medium - Four identical particles of mass \(m\) are kept at the four corners of a square. If the gravitational force exerted on one of the masses by the other masses is \(\left(\frac{2 \sqrt{2}+1}{32}\right) \frac{\mathrm{Gm}^2}{\mathrm{~L}^2}\), the length of the sides of the square is _______.JEE Mains 2024 Hard
- All resistances in figure are \(1\,\Omega\) each. The value of current ' \(I\) ' is \(\frac{a}{5}\,A\). The value of \(a\) is
JEE Mains 2022 Hard - A signal of \(0.1\, kW\) is transmitted in a cable. The attenuation of cable is \(-5 \,dB\) per \(km\) and cable length is \(20\, km\). The power received at receiver is \(10^{-x} \, W\). The value of \(x\) is ....... . \(\left[\right.\) Gain in \(\left. dB =10 \log _{10}\left(\frac{ P _{0}}{ P _{i}}\right)\right]\)JEE Mains 2021 Hard