JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2022
- Hard
- Numerical
All resistances in figure are \(1\,\Omega\) each. The value of current ' \(I\) ' is \(\frac{a}{5}\,A\). The value of \(a\) is

Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(8\)
Step-by-step Solution
Detailed explanation
\(R_{e q}=\frac{15 R}{8}=\frac{15}{8}\,\Omega\)
\(I=\frac{3}{\frac{15}{8}}=\frac{8}{5}\,A\)
\(\therefore a=8\)
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