JEE Mains · Physics · STD 12 - 3. current electricity
All resistances in figure are \(1\,\Omega\) each. The value of current ' \(I\) ' is \(\frac{a}{5}\,A\). The value of \(a\) is
- A \(8\)
- B \(2\)
- C \(1\)
- D \(11\)
Answer & Solution
Correct Answer
(A) \(8\)
Step-by-step Solution
Detailed explanation
\(R_{e q}=\frac{15 R}{8}=\frac{15}{8}\,\Omega\) \(I=\frac{3}{\frac{15}{8}}=\frac{8}{5}\,A\) \(\therefore a=8\)
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