JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
In the figure, potential difference between \(A\) and \(B\) is......\(V\)

- A \(5\)
- B \(10\)
- C \(0\)
- D \(15\)
Answer & Solution
Correct Answer
(B) \(10\)
Step-by-step Solution
Detailed explanation
\(\frac{30-\mathrm{V}_{\mathrm{A}}}{10}+\frac{0-\mathrm{V}_{\mathrm{A}}}{10}+\frac{0-\mathrm{V}_{\mathrm{A}}}{10}=0\) \(3=\frac{3 V_{A}}{10}\) \(\mathrm{V}_{\mathrm{A}}=10 \mathrm{V}\)
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