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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2020
  • Medium
  • Numerical

In the figure, potential difference between \(A\) and \(B\) is......\(V\)

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(B) \(10\)

Step-by-step Solution

Detailed explanation

\(\frac{30-\mathrm{V}_{\mathrm{A}}}{10}+\frac{0-\mathrm{V}_{\mathrm{A}}}{10}+\frac{0-\mathrm{V}_{\mathrm{A}}}{10}=0\)

\(3=\frac{3 V_{A}}{10}\)

\(\mathrm{V}_{\mathrm{A}}=10 \mathrm{V}\)

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