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JEE Mains · Physics · STD 11 - Gravitation
  • JEE Mains 2024
  • Hard
  • Numerical

A planet takes \(200\) days to complete one revolution around the Sun. If the distance of the planet from Sun is reduced to one fourth of the original distance, how many days will it take to complete one revolution?

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Answer & Solution

Correct Answer

(A) \(25\)

Step-by-step Solution

Detailed explanation

\( \mathrm{T}^2 \propto \mathrm{r}^3 \)

\( \frac{\mathrm{T}_1^2}{\mathrm{r}_1^3}=\frac{\mathrm{T}_2^2}{\mathrm{r}_2^3} \)

\( \frac{(200)^2}{\mathrm{r}^3}=\frac{\mathrm{T}_2^2}{\left(\frac{\mathrm{r}}{4}\right)^3} \)

\( \frac{200 \times 200}{4 \times 4 \times 4}=\mathrm{T}_2^2 \)

\( \mathrm{~T}_2=\frac{200}{4 \times 2} \)

\( \mathrm{~T}_2=25 \text { days }\)

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