JEE Mains · Physics · STD 11 - 7. gravitation
Two planets \(A\) and \(B\) of radii \(R\) and \(1.5 R\) have densities \(\rho\) and \(\rho / 2\) respectively. The ratio of acceleration due to gravity at the surface of \(B\) to \(A\) is :
- A \(2: 3\)
- B \(2: 1\)
- C \(3: 4\)
- D \(4: 3\)
Answer & Solution
Correct Answer
(C) \(3: 4\)
Step-by-step Solution
Detailed explanation
\(g =\frac{ GM }{ R ^2}=\frac{4}{3} \pi G \rho R\) \(\therefore \frac{ g _2}{ g _1}=\frac{\rho_2}{\rho_1} \times \frac{ R _2}{ R _1}=\frac{1}{2} \times 1.5=\frac{3}{4}\)
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